Electromagnetism

Electrostatics, Gauss

Problem

Calculate the electric field at a point P located at a distance r from the axis of a long cylindrical and homogeneous distribution of charge of density ρ and radius R.

Solution

Case 1 will be that P is outside the cylinder, in which case we consider an enclosing surface with the shape of a cylinder of radius r and height h.

According to Gauss

\( \oint \vec E . d\vec a = \dfrac {Q_{enclosed}} {\epsilon_0} \)

So, in this case

\( E 2\pi r h = \dfrac {\rho h \pi R^2} {\epsilon_0} \)

After simplication we get

\( E = \dfrac {\rho R^2} {2 \epsilon_0 r} \) for r > R

Notice that the electric field drops like 1/r as opposed to the usual 1/r2 for point charges.

Case 2 will be that P is inside the cylinder, in which case we consider again an enclosing surface with the shape of a cylinder of radius r and height h, but only the charge inside the cylinder of radius r will be enclosed.

So, in this case

\( E 2\pi r h = \dfrac {\rho h \pi r^2} {\epsilon_0} \)

After simplication we get

\( E = \dfrac {\rho r} {2 \epsilon_0} \) for r < R

Notice that the electric field is linearly proportional to r, which is the same for a uniformly charged sphere.